PHP5中文手册·Find position of first occurrence of a case-insensitive string -- 追寻梦想＞编程乐园＞PHP 编程

说明

int stripos ( string $haystack , string $needle [, int $offset ] )

Returns the numeric position of the first occurrence of needle in the haystack string.

Unlike strpos(), stripos() is case-insensitive.

参数

haystack

needle

Note that the needle may be a string of one or more characters.

If needle is not a string, it is converted to an integer and applied as the ordinal value of a character.

offset

The optional offset parameter allows you to specify which character in haystack to start searching. The position returned is still relative to the beginning of haystack .

返回值

If needle is not found, stripos() will return boolean FALSE.

Warning

本函数可能返回布尔值 FALSE，但也可能返回一个与 FALSE 等值的非布尔值，例如 0 或者 ""。请参阅布尔类型章节以获取更多信息。应使用 === 运算符来测试本函数的返回值。

范例

Example#1 stripos() examples


<?php
$findme    = 'a';
$mystring1 = 'xyz';
$mystring2 = 'ABC';

$pos1 = stripos($mystring1, $findme);
$pos2 = stripos($mystring2, $findme);

// Nope, 'a' is certainly not in 'xyz'
if ($pos1 === false) {
    echo "The string '$findme' was not found in the string '$mystring1'";
}

// Note our use of ===.  Simply == would not work as expected
// because the position of 'a' is the 0th (first) character.
if ($pos2 !== false) {
    echo "We found '$findme' in '$mystring2' at position $pos2";
}
?>

注释

Note: 本函数可安全用于二进制对象。


	PHP5中文手册 stripcslashes stripslashes Strings PHP Manual stripos (PHP 5) stripos — Find position of first occurrence of a case-insensitive string 说明 int stripos ( string `$haystack` , string `$needle` [, int `$offset` ] ) Returns the numeric position of the first occurrence of `needle` in the `haystack` string. Unlike strpos(), stripos() is case-insensitive. 参数 `haystack` `needle` Note that the `needle` may be a string of one or more characters. If `needle` is not a string, it is converted to an integer and applied as the ordinal value of a character. `offset` The optional `offset` parameter allows you to specify which character in `haystack` to start searching. The position returned is still relative to the beginning of `haystack` . 返回值 If `needle` is not found, stripos() will return boolean `FALSE`. Warning 本函数可能返回布尔值 `FALSE`，但也可能返回一个与 `FALSE` 等值的非布尔值，例如 0 或者 ""。请参阅布尔类型章节以获取更多信息。应使用 === 运算符来测试本函数的返回值。范例 Example#1 stripos() examples <?php $findme = 'a'; $mystring1 = 'xyz'; $mystring2 = 'ABC'; $pos1 = stripos($mystring1, $findme); $pos2 = stripos($mystring2, $findme); // Nope, 'a' is certainly not in 'xyz' if ($pos1 === false) { echo "The string '$findme' was not found in the string '$mystring1'"; } // Note our use of ===. Simply == would not work as expected // because the position of 'a' is the 0th (first) character. if ($pos2 !== false) { echo "We found '$findme' in '$mystring2' at position $pos2"; } ?> 注释 Note: 本函数可安全用于二进制对象。参见 strpos() strrpos() strrchr() substr() stristr() strstr() strripos() str_ireplace() stripcslashes stripslashes Strings PHP Manual

stripos

说明

参数

返回值

范例

注释

参见