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PHP5中文手册

strripos

(PHP 5)

strripos — Find position of last occurrence of a case-insensitive string in a string

说明

int strripos ( string $haystack , string $needle [, int $offset ] )

Find position of last occurrence of a case-insensitive string in a string. Unlike strrpos(), strripos() is case-insensitive.

参数

haystack

needle

Note that the needle may be a string of one or more characters.

offset

The offset parameter may be specified to begin searching an arbitrary number of characters into the string.

Negative offset values will start the search at offset characters from the start of the string.

返回值

Returns the numerical position of the last occurence of needle . Also note that string positions start at 0, and not 1.

If needle is not found, FALSE is returned.

Warning

本函数可能返回布尔值 FALSE,但也可能返回一个与 FALSE 等值的非布尔值,例如 0 或者 ""。请参阅布尔类型章节以获取更多信息。应使用 === 运算符来测试本函数的返回值。

范例

Example#1 A simple strripos() example

<?php
$haystack 
'ababcd';
$needle   'aB';

$pos      strripos($haystack$needle);

if (
$pos === false) {
    echo 
"Sorry, we did not find ($needle) in ($haystack)";
} else {
    echo 
"Congratulations!\n";
    echo 
"We found the last ($needle) in ($haystack) at position ($pos)";
}
?>

上例将输出:

   Congratulations!
   We found the last (aB) in (ababcd) at position (2)